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exit

Scheduled Pinned Locked Moved Programmer Humor
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  • S [email protected]

    Lemme golf that

    ~ $ python
    Python 3.12.10 (main, Apr  9 2025, 18:13:11) [Clang 18.0.3 (https://android.googlesource.com/toolchain/llvm-project d8003a456 on linux
    Type "help", "copyright", "credits" or "license" for more information.
    >>> class x:
    ...  def __repr__(s):
    ...   exit(0)
    ...
    >>> xit = x()
    >>> xit
    ~ $
    

    Not that hard

    B This user is from outside of this forum
    B This user is from outside of this forum
    [email protected]
    wrote on last edited by
    #13

    repr is generally assumed to be side effect free and cheap to run, so things like debuggers tend to show repr of things in scope, including possibly exit

    also then it behaves differently between repl and script, since repr never gets run. to do it properly it has to be a new repl keyword I imagine, but I still don't know if I'm sold on the idea

    S 1 Reply Last reply
    2
    • B [email protected]

      repr is generally assumed to be side effect free and cheap to run, so things like debuggers tend to show repr of things in scope, including possibly exit

      also then it behaves differently between repl and script, since repr never gets run. to do it properly it has to be a new repl keyword I imagine, but I still don't know if I'm sold on the idea

      S This user is from outside of this forum
      S This user is from outside of this forum
      [email protected]
      wrote on last edited by
      #14

      Good points. You're right, it does need solved at the shell level. Glad they did so.

      1 Reply Last reply
      1
      • R [email protected]

        That just gave me the idea that it would be fun to inspect exit a little.

        Which led me down this path:

        >>> repr(exit)
        'Use exit() or Ctrl-Z plus Return to exit'
        >>> dir(exit)
        [(...), 'eof', 'name']
        >>> exit.eof, exit.name
        ('Ctrl-Z plus Return', 'exit')
        

        Okay, cool, the "Use exit() etc." blurb appears because it's the function's repr, and the string is assembled from its name and eof properties.

        Now let's try to make our own:

        >>> exit.__class__
        <class '_sitebuiltins.Quitter'>
        >>> gtfo = exit.__class__()
        TypeError: Quitter.__init__() missing 2 required positional arguments: 'name' and 'eof'
        

        Oh Python, you shouldn't have.

        >>> gtfo = exit.__class__("a big puff of smoke", "a sneaky skedaddle")
        >>> gtfo
        Use a big puff of smoke() or a sneaky skedaddle to exit
        

        Beauty!

        M This user is from outside of this forum
        M This user is from outside of this forum
        [email protected]
        wrote on last edited by
        #15

        It never occurred me to inspect this, nice find.

        1 Reply Last reply
        2
        • ptz@dubvee.orgP [email protected]
          This post did not contain any content.
          somethingburger@jlai.luS This user is from outside of this forum
          somethingburger@jlai.luS This user is from outside of this forum
          [email protected]
          wrote on last edited by
          #16

          Same energy as "Option -h not recognized; use --help for the list of options".

          ptz@dubvee.orgP D 2 Replies Last reply
          9
          • somethingburger@jlai.luS [email protected]

            Same energy as "Option -h not recognized; use --help for the list of options".

            ptz@dubvee.orgP This user is from outside of this forum
            ptz@dubvee.orgP This user is from outside of this forum
            [email protected]
            wrote on last edited by
            #17

            I can actually forgive that one since it's the fallback for any invalid argument.

            rikudou@lemmings.worldR 1 Reply Last reply
            11
            • ptz@dubvee.orgP [email protected]

              I can actually forgive that one since it's the fallback for any invalid argument.

              rikudou@lemmings.worldR This user is from outside of this forum
              rikudou@lemmings.worldR This user is from outside of this forum
              [email protected]
              wrote on last edited by
              #18

              Not always, way too often you just get a variation of "invalid option, use --help to get a list of options"

              How about you show me by default like most apps?

              S 1 Reply Last reply
              1
              • R [email protected]

                That just gave me the idea that it would be fun to inspect exit a little.

                Which led me down this path:

                >>> repr(exit)
                'Use exit() or Ctrl-Z plus Return to exit'
                >>> dir(exit)
                [(...), 'eof', 'name']
                >>> exit.eof, exit.name
                ('Ctrl-Z plus Return', 'exit')
                

                Okay, cool, the "Use exit() etc." blurb appears because it's the function's repr, and the string is assembled from its name and eof properties.

                Now let's try to make our own:

                >>> exit.__class__
                <class '_sitebuiltins.Quitter'>
                >>> gtfo = exit.__class__()
                TypeError: Quitter.__init__() missing 2 required positional arguments: 'name' and 'eof'
                

                Oh Python, you shouldn't have.

                >>> gtfo = exit.__class__("a big puff of smoke", "a sneaky skedaddle")
                >>> gtfo
                Use a big puff of smoke() or a sneaky skedaddle to exit
                

                Beauty!

                L This user is from outside of this forum
                L This user is from outside of this forum
                [email protected]
                wrote on last edited by
                #19

                Obviously they need to make exit's repr method raise a SystemExit

                1 Reply Last reply
                1
                • rikudou@lemmings.worldR [email protected]

                  Not always, way too often you just get a variation of "invalid option, use --help to get a list of options"

                  How about you show me by default like most apps?

                  S This user is from outside of this forum
                  S This user is from outside of this forum
                  [email protected]
                  wrote on last edited by
                  #20

                  They meant that you'd get the same message no matter what unrecognized option you use. So it's not like they added a specific check that if you type in -h they will give you the message, but instead you get the same message for any unrecognized option.

                  The thing in the OP only occurs if you type exit, so they specifically added that message to be shown when the interpreter clearly knows what you want, but you just didn't say it exactly right.

                  rikudou@lemmings.worldR 1 Reply Last reply
                  1
                  • R [email protected]

                    That just gave me the idea that it would be fun to inspect exit a little.

                    Which led me down this path:

                    >>> repr(exit)
                    'Use exit() or Ctrl-Z plus Return to exit'
                    >>> dir(exit)
                    [(...), 'eof', 'name']
                    >>> exit.eof, exit.name
                    ('Ctrl-Z plus Return', 'exit')
                    

                    Okay, cool, the "Use exit() etc." blurb appears because it's the function's repr, and the string is assembled from its name and eof properties.

                    Now let's try to make our own:

                    >>> exit.__class__
                    <class '_sitebuiltins.Quitter'>
                    >>> gtfo = exit.__class__()
                    TypeError: Quitter.__init__() missing 2 required positional arguments: 'name' and 'eof'
                    

                    Oh Python, you shouldn't have.

                    >>> gtfo = exit.__class__("a big puff of smoke", "a sneaky skedaddle")
                    >>> gtfo
                    Use a big puff of smoke() or a sneaky skedaddle to exit
                    

                    Beauty!

                    S This user is from outside of this forum
                    S This user is from outside of this forum
                    [email protected]
                    wrote on last edited by
                    #21

                    Does gtfo() then work as expected?

                    1 Reply Last reply
                    0
                    • S [email protected]

                      They meant that you'd get the same message no matter what unrecognized option you use. So it's not like they added a specific check that if you type in -h they will give you the message, but instead you get the same message for any unrecognized option.

                      The thing in the OP only occurs if you type exit, so they specifically added that message to be shown when the interpreter clearly knows what you want, but you just didn't say it exactly right.

                      rikudou@lemmings.worldR This user is from outside of this forum
                      rikudou@lemmings.worldR This user is from outside of this forum
                      [email protected]
                      wrote on last edited by
                      #22

                      I mean, if I didn't use a correct flag, my next command will probably include -h / --help

                      S 1 Reply Last reply
                      0
                      • rikudou@lemmings.worldR [email protected]

                        I mean, if I didn't use a correct flag, my next command will probably include -h / --help

                        S This user is from outside of this forum
                        S This user is from outside of this forum
                        [email protected]
                        wrote on last edited by
                        #23

                        You aren't wrong, it wouldn't be bad for it to just print the help in that case, at least when running interactive.

                        For automation, printing the full help of a more complex command would completely trash logs.

                        1 Reply Last reply
                        0
                        • somethingburger@jlai.luS [email protected]

                          Same energy as "Option -h not recognized; use --help for the list of options".

                          D This user is from outside of this forum
                          D This user is from outside of this forum
                          [email protected]
                          wrote on last edited by
                          #24

                          Or more subtly, when the command uses BSD (nowadays Go) style single-dash args, so it wants -help and not --help.

                          1 Reply Last reply
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