Which of these javascript expressions is false?
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C, because yes.
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C, because yes.
I'd say C too because that's the only one that would be True in a normal programming language and this is javascript so...
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I'd say C too because that's the only one that would be True in a normal programming language and this is javascript so...
It's not true in a normal programming language. If it is true in yours, you should stop using it immediately.
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I'd say C too because that's the only one that would be True in a normal programming language and this is javascript so...
probably not true in most other langauges. although I'm not well versed in the way numbers are represented in code and what makes a number "NaN", something tells me the technical implications of that would be quite bad in a production environment.
the definitive way to check for NaN in JS would probably be something like
// with `num` being an unknown value // Convert value to a number const res = Number(num); /* * First check if the number is 0, since 0 is a falsy * value in JS, and if it isn't, `NaN` is the only other * falsy number value */ const isNaN = res !== 0 && !res; -
It's not true in a normal programming language. If it is true in yours, you should stop using it immediately.
A non type should be a type. It should be of the type none. And it is in good script languages like Python so I don't know why you think it shouldn't.
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A non type should be a type. It should be of the type none. And it is in good script languages like Python so I don't know why you think it shouldn't.
They say a picture is worth a thousand words.
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probably not true in most other langauges. although I'm not well versed in the way numbers are represented in code and what makes a number "NaN", something tells me the technical implications of that would be quite bad in a production environment.
the definitive way to check for NaN in JS would probably be something like
// with `num` being an unknown value // Convert value to a number const res = Number(num); /* * First check if the number is 0, since 0 is a falsy * value in JS, and if it isn't, `NaN` is the only other * falsy number value */ const isNaN = res !== 0 && !res;NaN is a special floating point value. https://en.wikipedia.org/wiki/IEEE_754
It's weird but it makes sense why it was chosen to be this way.
