Can anyone solve this math for me?
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Take a look at this page, it'll give you not only your answer but explain how to solve it
Dude so smart i was already breaking out the angles and testing everything out
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I teach this to my grade 9 class in Canada. It’s on the curriculum.
Nice. I have no recollection of seeing this before.
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No, sorry, I'm dumb.
Hello dumb! I'm dad
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if we assume the bottom right corner is a right angle and is the center of the arc, then it is solvable in the manners that others here have already described. if either of those is not the case, and the image itself doesn't state, then there is insufficient information to solve it.
You sure?
Draw line theta from left to right intersections and ya got two triangles.
Pythagoras gets you the length of that line. Trig gets you the two remaining angles of the red triangle (sohcahtoa!!)
180-angles gets you one angle of the new triangle. Then trig again gets you cos theta = x/length and you get the remaining angles. Maybe I left a step out but generally thats the process -
Nice. I have no recollection of seeing this before.
Tbf most Canadian grade 9 teachers skip it.
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Spent too long trying to figure out if this was loss or not.
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Shouldn't the person who to lazy to measure x solve this?
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24,7 and make a pythagorean triple with 25 as the hypotenuse. If the problem uses one pythagorean triple, it probably uses another, so I assume x is 15, and the radius is 20.
Not the most complete answer, but definitely the fastest one^^
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I'ma go with 8 because it's slightly longer than 7
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Spent too long trying to figure out if this was loss or not.
Well? Is it?
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Dude so smart i was already breaking out the angles and testing everything out
This is the worst way to go about doing it, because you should never assume a drawing is made to scale unless it is specifically marked as such. A protractor would be useless if the drawing isn’t to scale.
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This is the worst way to go about doing it, because you should never assume a drawing is made to scale unless it is specifically marked as such. A protractor would be useless if the drawing isn’t to scale.
I meant more like trying to use cos tan sin and the pythogoras thing not actually measuring it by hand haha
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The dashed lines lead to the bold line!
the answer is 15
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