Why would'nt this work?
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How heavy would a stick of this size weigh?
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What if you had a crane?
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But can you lift it from the moon? Gravity is a lot lower there.
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Weigh on Earth or on Moon?
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We're supposing that you have an herculean strengh and that weight is not a problem
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Large if factual
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The only way to know for sure is by trying
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Yes, about my setting, it was pretty much an excuse to illustrate the experiment, with like you said, a bit too much of magic.
The moon being on a straight distance of 1 light second, i didn't had found another place to put this experiment on. So I didn't take into account the herculean strengh needed, the movement of the earth and the moon and the gravity.
Someone gave a link to an answer of my question, with a more realistic take on the position of the other end, but your explanations are still welcome for this moon setting and the "moon elevator" problem
(i know i may have broken english sometimes, sorry about that)
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(i know i may have broken english sometimes, sorry about that)
Not at all! I couldn't tell you aren't a native speaker. Regarding a "moon elevator", or more realistically a space elevator, these kinds of Herculean physics problems are exactly what people are trying to iron out. The forces involved are astronomical.
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That was excellent. Thank you
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Or a duck.
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NASA: "Hold my beaker."
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Yeah IIRC that even applies to things like gravity as well. As in, we aren't actually orbiting around where is sun is, we're orbiting around where it was ~8 minutes ago because the sun is about 8 light-minutes from Earth.
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Oh right. I'll edit my comment
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Okay done i got his lids whos got the space gear and the impossible stick
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wave function (something that does not travel) collapses (something that does not move either) faster than light (themselves?)
this word soup does not make sense
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It's even wilder when you take the concept of ridgidity and transfer of energy out of the equation and just think in terms of pure information propagating though a light cone. Rigidity itself is a function of information.